Find the product of each of the following by suitable rearrangement:
`8xx625xx43`

Answer

To find the product of \( 8 \times 625 \times 43 \) using suitable rearrangement, we can follow these steps:

### Step 1: Rearranging the Numbers
We can rearrange the multiplication to make it easier. We will multiply \( 625 \) and \( 8 \) first because \( 8 \) can be broken down into smaller parts that make calculations simpler.

### Step 2: Multiply \( 625 \) by \( 8 \)
Now, let's calculate \( 625 \times 8 \).

\[ 625 \times 8 = 5000 \]

**Calculation Breakdown:**
- \( 8 \times 5 = 40 \) (write down 0, carry over 4)
- \( 8 \times 2 = 16 \) (add the carry over 4: \( 16 + 4 = 20 \), write down 0, carry over 2)
- \( 8 \times 6 = 48 \) (add the carry over 2: \( 48 + 2 = 50 \))

So, \( 625 \times 8 = 5000 \).

### Step 3: Multiply the Result by \( 43 \)
Next, we will multiply \( 5000 \) by \( 43 \).

\[ 5000 \times 43 \]

**Calculation Breakdown:**
- First, calculate \( 5000 \times 3 \):
\[ 5000 \times 3 = 15000 \]

- Next, calculate \( 5000 \times 40 \):
\[ 5000 \times 40 = 200000 \]

- Now, add both results together:
\[ 15000 + 200000 = 215000 \]

### Final Answer
Thus, the product of \( 8 \times 625 \times 43 \) is \( 215000 \).

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