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Solve : [3{4-9+7(30-:6+8)-2xx4}]-30...

Solve :
`[3{4-9+7(30-:6+8)-2xx4}]-30`

A

`284`

B

`204`

C

`200`

D

`214`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression `[3{4-9+7(30-:6+8)-2xx4}]-30`, we will follow the BODMAS rule, which stands for Brackets, Orders (i.e., powers and square roots, etc.), Division, Multiplication, Addition, and Subtraction. ### Step-by-Step Solution: 1. **Identify the expression**: We start with the expression: \[ 3 \{ 4 - 9 + 7(30 \div 6 + 8) - 2 \times 4 \} - 30 \] 2. **Solve inside the brackets**: First, we need to solve the expression inside the brackets, specifically `30 ÷ 6 + 8`. \[ 30 \div 6 = 5 \] Now, add 8: \[ 5 + 8 = 13 \] So, we replace `30 ÷ 6 + 8` with `13` in the original expression: \[ 3 \{ 4 - 9 + 7 \times 13 - 2 \times 4 \} - 30 \] 3. **Multiply**: Next, we perform the multiplication: \[ 7 \times 13 = 91 \] and \[ 2 \times 4 = 8 \] Now, substitute these values back into the expression: \[ 3 \{ 4 - 9 + 91 - 8 \} - 30 \] 4. **Simplify inside the brackets**: Now, simplify the expression inside the brackets: \[ 4 - 9 = -5 \] Then add `91`: \[ -5 + 91 = 86 \] Finally, subtract `8`: \[ 86 - 8 = 78 \] So, we now have: \[ 3 \times 78 - 30 \] 5. **Multiply by 3**: Now, multiply: \[ 3 \times 78 = 234 \] 6. **Subtract 30**: Finally, subtract `30` from `234`: \[ 234 - 30 = 204 \] ### Final Answer: The final answer is: \[ \boxed{204} \]
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