Home
Class 6
MATHS
State if the result is always odd or alw...

State if the result is always odd or always even:
Two consecutive odd numbers are added

Text Solution

AI Generated Solution

The correct Answer is:
To determine whether the sum of two consecutive odd numbers is always odd or always even, we can follow these steps: ### Step 1: Define the consecutive odd numbers Let the first odd number be represented as \( n \). Since we are dealing with consecutive odd numbers, the next consecutive odd number can be represented as \( n + 2 \). ### Step 2: Write the expression for their sum Now, we can write the sum of these two consecutive odd numbers: \[ \text{Sum} = n + (n + 2) \] ### Step 3: Simplify the expression Now, let's simplify the expression: \[ \text{Sum} = n + n + 2 = 2n + 2 \] ### Step 4: Factor the expression We can factor out the common term: \[ \text{Sum} = 2(n + 1) \] ### Step 5: Analyze the result The expression \( 2(n + 1) \) indicates that the sum is a multiple of 2. Since any multiple of 2 is even, we can conclude that the sum of two consecutive odd numbers is always even. ### Conclusion Thus, the result of adding two consecutive odd numbers is always even. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

State if the result is always odd or always even: Two consecutive numbers are multiplied

State if the result is always odd or always even: One even and two odd numbers are added

State if the result is always odd or always even: Two even numbers are added.

State if the result is always odd or always even: Three odd numbers are added

State if the result is always odd or always even: Two odd numbers are added

State if the result is always odd or always even: Three odd number are multiplied

State if the result is always odd or always even: Two prime numbers greater than 2 are added

Find four consecutive odd numbers whose sum is 136.

The HCF of two consecutive odd numbers is ............

Write four consecutive odd integers preceding 3.