Jatin got `31/(4)`kg of sweets of which `29/(6)`kg were spoiled. How much was left with Jatin ?

Answer

To solve the problem step by step, we need to find out how much sweets Jatin has left after some were spoiled.

### Step-by-Step Solution:

1. **Identify the total amount of sweets and the spoiled amount:**
- Total sweets Jatin got: \( \frac{31}{4} \) kg
- Spoiled sweets: \( \frac{29}{6} \) kg

2. **Set up the equation to find the remaining sweets:**
- Remaining sweets = Total sweets - Spoiled sweets
- This can be written as:
\[ \text{Remaining sweets} = \frac{31}{4} - \frac{29}{6} \]

3. **Find the least common multiple (LCM) of the denominators (4 and 6):**
- The multiples of 4 are: 4, 8, 12, 16, ...
- The multiples of 6 are: 6, 12, 18, ...
- The LCM of 4 and 6 is 12.

4. **Convert each fraction to have the same denominator (12):**
- For \( \frac{31}{4} \):
\[ \frac{31}{4} = \frac{31 \times 3}{4 \times 3} = \frac{93}{12} \]
- For \( \frac{29}{6} \):
\[ \frac{29}{6} = \frac{29 \times 2}{6 \times 2} = \frac{58}{12} \]

5. **Subtract the two fractions:**
- Now we can subtract:
\[ \frac{93}{12} - \frac{58}{12} = \frac{93 - 58}{12} = \frac{35}{12} \]

6. **Conclusion:**
- Jatin has \( \frac{35}{12} \) kg of sweets left.

### Final Answer:
Jatin has \( \frac{35}{12} \) kg of sweets left.

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