In setion A of 40 students, 36 students get more than `80%` marks. In section B of 36 students got more than `80%` marks. In which section did a greater fraction of students score more than `80%`?

Answer

To solve the problem, we need to find the fraction of students who scored more than 80% in both sections A and B, and then compare these fractions.

### Step-by-Step Solution:

1. **Identify the total number of students in each section:**
- Section A has 40 students.
- Section B has 36 students.

2. **Identify the number of students who scored more than 80% in each section:**
- In Section A, 36 students scored more than 80%.
- In Section B, all 36 students scored more than 80%.

3. **Calculate the fraction of students who scored more than 80% in Section A:**
\[ \text{Fraction in Section A} = \frac{\text{Number of students scoring more than 80%}}{\text{Total number of students}} = \frac{36}{40} \]
- Simplifying \(\frac{36}{40}\):
\[ \frac{36 \div 4}{40 \div 4} = \frac{9}{10} \]

4. **Calculate the fraction of students who scored more than 80% in Section B:**
\[ \text{Fraction in Section B} = \frac{36}{36} = 1 \]

5. **Compare the two fractions:**
- Fraction in Section A: \(\frac{9}{10}\)
- Fraction in Section B: \(1\)

6. **Conclusion:**
Since \(1\) (or \(100\%\)) is greater than \(\frac{9}{10}\) (or \(90\%\)), a greater fraction of students scored more than 80% in Section B.

### Final Answer:
A greater fraction of students scored more than 80% in Section B.