Fill up the `square` using `ltorgtor=`, so that the statement should be true.
`3/(14) square 2/(28)`

Answer

To solve the problem \( \frac{3}{14} \, \square \, \frac{2}{28} \), we need to compare the two fractions. Since the denominators are different, we will first make them the same.

### Step 1: Identify the denominators
The denominators of the fractions are 14 and 28.

### Step 2: Make the denominators the same
To compare the fractions easily, we can convert \( \frac{3}{14} \) to a fraction with a denominator of 28. We can do this by multiplying both the numerator and the denominator of \( \frac{3}{14} \) by 2.

\[ \frac{3}{14} = \frac{3 \times 2}{14 \times 2} = \frac{6}{28} \]

### Step 3: Rewrite the comparison
Now we can rewrite the comparison with the same denominator:

\[ \frac{6}{28} \, \square \, \frac{2}{28} \]

### Step 4: Compare the numerators
Now that we have the same denominator, we can compare the numerators:

- The numerator of the first fraction is 6.
- The numerator of the second fraction is 2.

Since \( 6 > 2 \), we can conclude:

\[ \frac{6}{28} > \frac{2}{28} \]

### Step 5: Fill in the box
Thus, we can fill in the box with the greater than sign:

\[ \frac{3}{14} \, > \, \frac{2}{28} \]

### Final Answer:
\[ \frac{3}{14} \, > \, \frac{2}{28} \]

---