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Find: 1(10)/(21)+2(1)/(6)...

Find:
`1(10)/(21)+2(1)/(6)`

A

`3(9)/(14)`

B

`3(8)/(14)`

C

`3(7)/(14)`

D

`3(6)/(14)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( 1\frac{10}{21} + 2\frac{1}{6} \), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we need to convert the mixed numbers into improper fractions. For \( 1\frac{10}{21} \): - Multiply the whole number (1) by the denominator (21): \[ 1 \times 21 = 21 \] - Add the numerator (10) to this product: \[ 21 + 10 = 31 \] - So, \( 1\frac{10}{21} \) becomes: \[ \frac{31}{21} \] For \( 2\frac{1}{6} \): - Multiply the whole number (2) by the denominator (6): \[ 2 \times 6 = 12 \] - Add the numerator (1) to this product: \[ 12 + 1 = 13 \] - So, \( 2\frac{1}{6} \) becomes: \[ \frac{13}{6} \] ### Step 2: Add the Improper Fractions Now we need to add \( \frac{31}{21} \) and \( \frac{13}{6} \). To do this, we need a common denominator. ### Step 3: Find the Least Common Multiple (LCM) The denominators are 21 and 6. We need to find the LCM of these two numbers. - The prime factorization of 21 is \( 3 \times 7 \). - The prime factorization of 6 is \( 2 \times 3 \). The LCM is found by taking the highest power of each prime: - From 21: \( 3^1 \) and \( 7^1 \) - From 6: \( 2^1 \) Thus, the LCM is: \[ 2^1 \times 3^1 \times 7^1 = 2 \times 3 \times 7 = 42 \] ### Step 4: Convert Each Fraction to Have the Common Denominator Now we convert each fraction to have a denominator of 42. For \( \frac{31}{21} \): - Multiply the numerator and denominator by 2: \[ \frac{31 \times 2}{21 \times 2} = \frac{62}{42} \] For \( \frac{13}{6} \): - Multiply the numerator and denominator by 7: \[ \frac{13 \times 7}{6 \times 7} = \frac{91}{42} \] ### Step 5: Add the Converted Fractions Now we can add the two fractions: \[ \frac{62}{42} + \frac{91}{42} = \frac{62 + 91}{42} = \frac{153}{42} \] ### Step 6: Simplify the Result (if possible) Now we simplify \( \frac{153}{42} \). We can check if there are any common factors. The GCD of 153 and 42 is 3. So we divide both the numerator and denominator by 3: \[ \frac{153 \div 3}{42 \div 3} = \frac{51}{14} \] ### Final Answer Thus, the final answer is: \[ \frac{51}{14} \]
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