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Find: 3(1)/(8)+1(5)/(12)...

Find:
`3(1)/(8)+1(5)/(12)`

A

` 4(13)/(24)`

B

` 4(15)/(24)`

C

` 4(17)/(24)`

D

` 4(19)/(24)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( 3\frac{1}{8} + 1\frac{5}{12} \), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we need to convert the mixed numbers into improper fractions. For \( 3\frac{1}{8} \): - Multiply the whole number (3) by the denominator (8): \[ 3 \times 8 = 24 \] - Add the numerator (1) to this product: \[ 24 + 1 = 25 \] - So, \( 3\frac{1}{8} \) becomes: \[ \frac{25}{8} \] For \( 1\frac{5}{12} \): - Multiply the whole number (1) by the denominator (12): \[ 1 \times 12 = 12 \] - Add the numerator (5) to this product: \[ 12 + 5 = 17 \] - So, \( 1\frac{5}{12} \) becomes: \[ \frac{17}{12} \] ### Step 2: Add the Improper Fractions Now we need to add \( \frac{25}{8} + \frac{17}{12} \). To do this, we need a common denominator. ### Step 3: Find the Least Common Multiple (LCM) The denominators are 8 and 12. We need to find the LCM of these two numbers. - The prime factorization of 8 is \( 2^3 \). - The prime factorization of 12 is \( 2^2 \times 3^1 \). The LCM will take the highest power of each prime: - For 2, the highest power is \( 2^3 \). - For 3, the highest power is \( 3^1 \). Thus, \[ \text{LCM} = 2^3 \times 3^1 = 8 \times 3 = 24 \] ### Step 4: Convert Fractions to Have a Common Denominator Now we convert both fractions to have the common denominator of 24. For \( \frac{25}{8} \): - Multiply the numerator and denominator by 3: \[ \frac{25 \times 3}{8 \times 3} = \frac{75}{24} \] For \( \frac{17}{12} \): - Multiply the numerator and denominator by 2: \[ \frac{17 \times 2}{12 \times 2} = \frac{34}{24} \] ### Step 5: Add the Converted Fractions Now we can add the two fractions: \[ \frac{75}{24} + \frac{34}{24} = \frac{75 + 34}{24} = \frac{109}{24} \] ### Step 6: Simplify the Result The fraction \( \frac{109}{24} \) is already in its simplest form. ### Final Answer Thus, the final answer is: \[ \frac{109}{24} \] ---
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