Find the sum:
`3(1)/(2)+7`

Answer

To find the sum of \(3 \frac{1}{2} + 7\), we can follow these steps:

### Step 1: Convert the mixed number to an improper fraction
First, we convert \(3 \frac{1}{2}\) into an improper fraction.

To do this:
- Multiply the whole number (3) by the denominator (2):
\[ 3 \times 2 = 6 \]
- Add the numerator (1) to this result:
\[ 6 + 1 = 7 \]
- Therefore, \(3 \frac{1}{2}\) can be written as:
\[ \frac{7}{2} \]

### Step 2: Write the second number as a fraction
Next, we need to express \(7\) as a fraction with the same denominator (2):
\[ 7 = \frac{7 \times 2}{2} = \frac{14}{2} \]

### Step 3: Add the two fractions
Now we can add the two fractions:
\[ \frac{7}{2} + \frac{14}{2} = \frac{7 + 14}{2} = \frac{21}{2} \]

### Final Answer
Thus, the sum of \(3 \frac{1}{2} + 7\) is:
\[ \frac{21}{2} \]

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