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Suman had 24 sweets, Kiran had 36 sweet...

Suman had 24 sweets, Kiran had 36 sweets and Preeti had 15 sweets. Suman ate 8 sweets, Kiran ate 12 and Preeti ate 5 sweets. What fraction of their own sweets are they left with?

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To solve the problem step by step, we will calculate the fraction of sweets each person has left after eating some of them. ### Step 1: Calculate the sweets left for Suman - **Total sweets Suman had**: 24 - **Sweets Suman ate**: 8 - **Sweets left**: 24 - 8 = 16 **Fraction of sweets left**: \[ \text{Fraction left} = \frac{\text{sweets left}}{\text{total sweets}} = \frac{16}{24} \] ### Step 2: Simplify the fraction for Suman - To simplify \(\frac{16}{24}\), we find the greatest common divisor (GCD) of 16 and 24, which is 8. - Divide both the numerator and the denominator by 8: \[ \frac{16 \div 8}{24 \div 8} = \frac{2}{3} \] ### Step 3: Calculate the sweets left for Kiran - **Total sweets Kiran had**: 36 - **Sweets Kiran ate**: 12 - **Sweets left**: 36 - 12 = 24 **Fraction of sweets left**: \[ \text{Fraction left} = \frac{24}{36} \] ### Step 4: Simplify the fraction for Kiran - To simplify \(\frac{24}{36}\), we find the GCD of 24 and 36, which is 12. - Divide both the numerator and the denominator by 12: \[ \frac{24 \div 12}{36 \div 12} = \frac{2}{3} \] ### Step 5: Calculate the sweets left for Preeti - **Total sweets Preeti had**: 15 - **Sweets Preeti ate**: 5 - **Sweets left**: 15 - 5 = 10 **Fraction of sweets left**: \[ \text{Fraction left} = \frac{10}{15} \] ### Step 6: Simplify the fraction for Preeti - To simplify \(\frac{10}{15}\), we find the GCD of 10 and 15, which is 5. - Divide both the numerator and the denominator by 5: \[ \frac{10 \div 5}{15 \div 5} = \frac{2}{3} \] ### Final Answer - **Suman's fraction of sweets left**: \(\frac{2}{3}\) - **Kiran's fraction of sweets left**: \(\frac{2}{3}\) - **Preeti's fraction of sweets left**: \(\frac{2}{3}\) All three have the same fraction of sweets left, which is \(\frac{2}{3}\).
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