Simran has a box of sweets which is `7/(8)` full. Anu's sweet box is `4/(5)` full. Who has more sweets?

Answer

To determine who has more sweets between Simran and Anu, we need to compare the fractions representing the fullness of their sweet boxes: Simran has \( \frac{7}{8} \) and Anu has \( \frac{4}{5} \).

### Step-by-Step Solution:

1. **Identify the fractions**:
- Simran's box: \( \frac{7}{8} \)
- Anu's box: \( \frac{4}{5} \)

2. **Find a common denominator**:
- The denominators are 8 and 5. We need to find the least common multiple (LCM) of these two numbers.
- The LCM of 8 and 5 is 40.

3. **Convert the fractions to have the same denominator**:
- For Simran's fraction \( \frac{7}{8} \):
- Multiply both the numerator and the denominator by 5 (since \( 40 \div 8 = 5 \)):
\[ \frac{7 \times 5}{8 \times 5} = \frac{35}{40} \]
- For Anu's fraction \( \frac{4}{5} \):
- Multiply both the numerator and the denominator by 8 (since \( 40 \div 5 = 8 \)):
\[ \frac{4 \times 8}{5 \times 8} = \frac{32}{40} \]

4. **Compare the two fractions**:
- Now we have:
- Simran: \( \frac{35}{40} \)
- Anu: \( \frac{32}{40} \)
- Since \( \frac{35}{40} > \frac{32}{40} \), we can conclude that Simran has more sweets.

5. **Final Conclusion**:
- Simran has more sweets in her box than Anu.