Find the value of each of the following algebraic expressions.
20y - 32 + 18x, for y = 3 and x = -2

Answer

To find the value of the algebraic expression \(20y - 32 + 18x\) for \(y = 3\) and \(x = -2\), we will follow these steps:

### Step 1: Substitute the values of \(y\) and \(x\) into the expression.
We start with the expression:
\[ 20y - 32 + 18x \]
Substituting \(y = 3\) and \(x = -2\):
\[ 20(3) - 32 + 18(-2) \]

### Step 2: Perform the multiplication.
Now, we calculate the multiplication:
\[ 20 \times 3 = 60 \]
\[ 18 \times -2 = -36 \]
So, we can rewrite the expression as:
\[ 60 - 32 - 36 \]

### Step 3: Perform the subtraction.
Now, we will simplify \(60 - 32\):
\[ 60 - 32 = 28 \]
Now, we have:
\[ 28 - 36 \]

### Step 4: Subtract the remaining values.
Now, we subtract \(36\) from \(28\):
\[ 28 - 36 = -8 \]

### Final Answer:
Thus, the value of the expression \(20y - 32 + 18x\) when \(y = 3\) and \(x = -2\) is:
\[ \boxed{-8} \]

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