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In a class of 40 students, ratio of stud...

In a class of 40 students, ratio of students who like badminton to those who like cricket is `3:8 and ` the ratio of students who like tennis to those who like cricket is `2:5.` Which is the more loved sport in the class after cricket ?

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To solve the problem step by step, we will analyze the given ratios and find the number of students who like each sport. ### Step 1: Understand the Ratios We are given two ratios: 1. The ratio of students who like badminton to those who like cricket is \(3:8\). 2. The ratio of students who like tennis to those who like cricket is \(2:5\). ### Step 2: Assign Variables Let: - The number of students who like badminton be \(3x\). - The number of students who like cricket be \(8x\). - The number of students who like tennis be \(2y\). - The number of students who like cricket (again) be \(5y\). ### Step 3: Equate the Cricket Values Since both ratios include cricket, we can equate the values of cricket: \[ 8x = 5y \] ### Step 4: Solve for One Variable From the equation \(8x = 5y\), we can express \(y\) in terms of \(x\): \[ y = \frac{8x}{5} \] ### Step 5: Find Total Students The total number of students in the class is 40. Therefore, we can express the total number of students as: \[ 3x + 8x + 2y = 40 \] Substituting \(y\) from Step 4 into the equation: \[ 3x + 8x + 2\left(\frac{8x}{5}\right) = 40 \] \[ 11x + \frac{16x}{5} = 40 \] ### Step 6: Clear the Fraction To eliminate the fraction, multiply the entire equation by 5: \[ 5(11x) + 16x = 200 \] \[ 55x + 16x = 200 \] \[ 71x = 200 \] ### Step 7: Solve for \(x\) Now we can solve for \(x\): \[ x = \frac{200}{71} \] ### Step 8: Calculate the Number of Students Now we can find the number of students for each sport: 1. **Cricket**: \[ 8x = 8 \times \frac{200}{71} = \frac{1600}{71} \approx 22.54 \] (approximately 23 students) 2. **Badminton**: \[ 3x = 3 \times \frac{200}{71} = \frac{600}{71} \approx 8.45 \] (approximately 8 students) 3. **Tennis**: Substitute \(y\) back to find tennis: \[ y = \frac{8x}{5} = \frac{8 \times \frac{200}{71}}{5} = \frac{320}{71} \approx 4.51 \] (approximately 4 students) \[ 2y = 2 \times \frac{320}{71} = \frac{640}{71} \approx 9 \] (approximately 9 students) ### Step 9: Conclusion From our calculations: - Students who like cricket: approximately 23 - Students who like badminton: approximately 8 - Students who like tennis: approximately 9 Thus, after cricket, the sport that is more loved is **tennis**.
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