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A milkman mixes water and milk in the ra...

A milkman mixes water and milk in the ratio 3:7, while the milk sold by other milkman has water and
milk in the ratio 4:11. Who is selling a better quality milk in terms of greater milk content in it?

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To determine which milkman is selling better quality milk in terms of greater milk content, we need to analyze the ratios of milk to water for both milkmen. ### Step-by-Step Solution: 1. **Identify the Ratios**: - The first milkman mixes water and milk in the ratio of 3:7. - The second milkman mixes water and milk in the ratio of 4:11. 2. **Calculate the Total Parts**: - For the first milkman: - Total parts = Water + Milk = 3 + 7 = 10 parts. - For the second milkman: - Total parts = Water + Milk = 4 + 11 = 15 parts. 3. **Calculate the Milk Content**: - For the first milkman: - Milk content = (Milk parts / Total parts) = 7 / 10 = 0.7 or 70%. - For the second milkman: - Milk content = (Milk parts / Total parts) = 11 / 15 = 0.7333 or approximately 73.33%. 4. **Compare the Milk Contents**: - First milkman: 70% milk content. - Second milkman: approximately 73.33% milk content. 5. **Conclusion**: - Since 73.33% (second milkman) is greater than 70% (first milkman), the second milkman is selling better quality milk in terms of greater milk content. ### Final Answer: The second milkman is selling better quality milk.
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