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Sujay eats 2 (2)/(3) packets of cookies ...

Sujay eats `2 (2)/(3)` packets of cookies in a day. How many packets of cookies will he eat in `17 (1)/(2)` days?

A

`= 86 (2)/(3)`

B

`= 46 (2)/(9)`

C

`= 49 (2)/(3)`

D

`= 46 (2)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many packets of cookies Sujay will eat in `17 (1)/(2)` days, we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we need to convert the mixed numbers into improper fractions. 1. **Convert `2 (2)/(3)` to an improper fraction:** - Multiply the whole number (2) by the denominator (3): \(2 \times 3 = 6\) - Add the numerator (2) to this result: \(6 + 2 = 8\) - So, \(2 (2)/(3) = \frac{8}{3}\). 2. **Convert `17 (1)/(2)` to an improper fraction:** - Multiply the whole number (17) by the denominator (2): \(17 \times 2 = 34\) - Add the numerator (1) to this result: \(34 + 1 = 35\) - So, \(17 (1)/(2) = \frac{35}{2}\). ### Step 2: Multiply the Fractions Now, we will multiply the number of packets Sujay eats in one day by the number of days. \[ \text{Total packets} = \left(\frac{8}{3}\right) \times \left(\frac{35}{2}\right) \] ### Step 3: Perform the Multiplication Multiply the numerators and the denominators: \[ \text{Numerator: } 8 \times 35 = 280 \] \[ \text{Denominator: } 3 \times 2 = 6 \] So, we have: \[ \text{Total packets} = \frac{280}{6} \] ### Step 4: Simplify the Fraction Now, we simplify \(\frac{280}{6}\): - Find the greatest common divisor (GCD) of 280 and 6, which is 2. - Divide both the numerator and the denominator by 2: \[ \frac{280 \div 2}{6 \div 2} = \frac{140}{3} \] ### Step 5: Convert to Mixed Number Now, we convert \(\frac{140}{3}\) to a mixed number: 1. Divide 140 by 3: - \(140 \div 3 = 46\) remainder \(2\). 2. So, \(\frac{140}{3} = 46 \frac{2}{3}\). ### Final Answer Sujay will eat \(46 \frac{2}{3}\) packets of cookies in \(17 (1)/(2)\) days. ---
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