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Evaluate: b. 2 (5)/(9) + 3 (7)/(15)...

Evaluate: b. `2 (5)/(9) + 3 (7)/(15)`

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To evaluate the expression \( 2 \frac{5}{9} + 3 \frac{7}{15} \), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we need to convert the mixed numbers into improper fractions. 1. For \( 2 \frac{5}{9} \): \[ 2 \frac{5}{9} = \frac{2 \times 9 + 5}{9} = \frac{18 + 5}{9} = \frac{23}{9} \] 2. For \( 3 \frac{7}{15} \): \[ 3 \frac{7}{15} = \frac{3 \times 15 + 7}{15} = \frac{45 + 7}{15} = \frac{52}{15} \] So, we have: \[ 2 \frac{5}{9} + 3 \frac{7}{15} = \frac{23}{9} + \frac{52}{15} \] ### Step 2: Find the Least Common Multiple (LCM) Next, we need to find the LCM of the denominators \( 9 \) and \( 15 \). - The prime factorization of \( 9 \) is \( 3^2 \). - The prime factorization of \( 15 \) is \( 3^1 \times 5^1 \). The LCM is found by taking the highest power of each prime: \[ \text{LCM}(9, 15) = 3^2 \times 5^1 = 9 \times 5 = 45 \] ### Step 3: Convert Fractions to Have the Same Denominator Now, we convert both fractions to have the same denominator of \( 45 \). 1. For \( \frac{23}{9} \): \[ \frac{23}{9} = \frac{23 \times 5}{9 \times 5} = \frac{115}{45} \] 2. For \( \frac{52}{15} \): \[ \frac{52}{15} = \frac{52 \times 3}{15 \times 3} = \frac{156}{45} \] Now we have: \[ \frac{23}{9} + \frac{52}{15} = \frac{115}{45} + \frac{156}{45} \] ### Step 4: Add the Fractions Now, we can add the two fractions: \[ \frac{115}{45} + \frac{156}{45} = \frac{115 + 156}{45} = \frac{271}{45} \] ### Step 5: Convert to Mixed Number Finally, we convert \( \frac{271}{45} \) into a mixed number. 1. Divide \( 271 \) by \( 45 \): \[ 271 \div 45 = 6 \quad \text{(since \( 45 \times 6 = 270 \))} \] The remainder is: \[ 271 - 270 = 1 \] So, we can write: \[ \frac{271}{45} = 6 \frac{1}{45} \] ### Final Answer Thus, the final answer is: \[ 6 \frac{1}{45} \] ---
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