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Find: e. (21)/(32) div 1 (14)/(35)...

Find: e. `(21)/(32) div 1 (14)/(35)`

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To solve the problem \( \frac{21}{32} \div 1 \frac{14}{35} \), we will follow these steps: ### Step 1: Convert the mixed fraction to an improper fraction The mixed fraction \( 1 \frac{14}{35} \) can be converted to an improper fraction. To do this, we multiply the whole number (1) by the denominator (35) and then add the numerator (14): \[ 1 \frac{14}{35} = \frac{1 \times 35 + 14}{35} = \frac{35 + 14}{35} = \frac{49}{35} \] ### Step 2: Rewrite the division as multiplication Now we rewrite the division of fractions as multiplication by the reciprocal of the second fraction: \[ \frac{21}{32} \div \frac{49}{35} = \frac{21}{32} \times \frac{35}{49} \] ### Step 3: Simplify the fractions Next, we simplify the fractions before multiplying. We can cancel out common factors: 1. The numerator \( 21 \) can be factored as \( 3 \times 7 \). 2. The denominator \( 49 \) can be factored as \( 7 \times 7 \). 3. The numerator \( 35 \) can be factored as \( 5 \times 7 \). Now we can cancel: - \( 21 \) and \( 49 \) share a common factor of \( 7 \): \[ \frac{21}{49} = \frac{3}{7} \] - \( 35 \) and \( 32 \) do not share any common factors, so we keep them as they are. Now we have: \[ \frac{3}{32} \times \frac{5}{7} \] ### Step 4: Multiply the fractions Now we multiply the numerators and the denominators: \[ \frac{3 \times 5}{32 \times 7} = \frac{15}{224} \] ### Final Answer Thus, the final answer is: \[ \frac{15}{224} \] ---
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ICSE-FRACTIONS-Exercise 2.3
  1. Find: c. (16)/(25) div (36)/(15)

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  2. Find: d. (4)/(25) div (16)/( 35)

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  3. Find: e. (21)/(32) div 1 (14)/(35)

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  4. Find: f. 1 (13)/(5) div 1 (5)/(7)

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  5. Simplify : a. ((4)/(7) div (36)/(49)) - (1)/(2)

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  6. Simplify : b. (5)/(9) div ((3)/(10) xx (5)/(12))

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  7. Simplify : c. (3)/(5) of ((1)/(15) xx 3 (2)/(5))

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  8. Simplify : d. (1)/(6) of (1 (1)/(9) div 7 (1)/(2) )

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  9. Simplify : e. 5 (1)/(3) xx (3)/(8) - (7)/(9) div 2 (1)/(10)

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  10. Simplify : f. (13)/(7) + 4 (4)/(5) xx (3)/(4) div (7)/(15)

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  11. Simplify : g. ((3)/(8) xx (2)/(15)) + ((4)/(9) div (32)/(27))

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  12. Simplify : ((6)/(7) div (2)/(5)) + ((5)/(9) div (27)/( 25))

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  13. Simplify : i. (1 (5)/(7) xx (7)/(10) ) - ((3)/(5) div (9)/(10))

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  14. Simplify : j. ((21)/(10) xx (2)/(14) ) - ((1)/(7) div (36)/(28))

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  15. Amit buys chocolates worth Rs. 97 (1)/(2). If one chocolate costs Rs. ...

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  16. One banana costs Rs. 5 (3)/(4). How many bananas can be bought for Rs....

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  17. A box of candies weighs 640 (1)/(2) g. If each candy weighs 45 (3)/(4)...

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  18. Suraj has to distribute 9 kg of sweets into 40 boxes. Find the quantit...

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  19. Suman covers 2 (4)/(5) km in (7)/(12) hours. a. How much time is req...

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  20. Suman covers 2 (4)/(5) km in (7)/(12) hours. b. How much will Suman ...

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