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Simplify : ((6)/(7) div (2)/(5)) + ((5)/...

Simplify : `((6)/(7) div (2)/(5)) + ((5)/(9) div (27)/( 25))`

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To simplify the expression \(\frac{6}{7} \div \frac{2}{5} + \frac{5}{9} \div \frac{27}{25}\), we can follow these steps: ### Step 1: Rewrite the Division as Multiplication We know that dividing by a fraction is the same as multiplying by its reciprocal. Therefore, we can rewrite the expression as follows: \[ \frac{6}{7} \div \frac{2}{5} = \frac{6}{7} \times \frac{5}{2} \] \[ \frac{5}{9} \div \frac{27}{25} = \frac{5}{9} \times \frac{25}{27} \] ### Step 2: Simplify Each Multiplication Now, we can simplify each multiplication: 1. For \(\frac{6}{7} \times \frac{5}{2}\): - Multiply the numerators: \(6 \times 5 = 30\) - Multiply the denominators: \(7 \times 2 = 14\) - So, \(\frac{6}{7} \times \frac{5}{2} = \frac{30}{14}\) 2. For \(\frac{5}{9} \times \frac{25}{27}\): - Multiply the numerators: \(5 \times 25 = 125\) - Multiply the denominators: \(9 \times 27 = 243\) - So, \(\frac{5}{9} \times \frac{25}{27} = \frac{125}{243}\) ### Step 3: Add the Two Results Now we need to add \(\frac{30}{14}\) and \(\frac{125}{243}\). To do this, we need a common denominator. ### Step 4: Find the Least Common Multiple (LCM) The denominators are 14 and 243. The LCM of 14 and 243 can be calculated as follows: - The prime factorization of 14 is \(2 \times 7\). - The prime factorization of 243 is \(3^5\). - The LCM is \(2 \times 7 \times 3^5 = 1701\). ### Step 5: Convert Each Fraction to the Common Denominator Now we convert each fraction to have the denominator of 1701: 1. For \(\frac{30}{14}\): - Multiply both the numerator and denominator by \(\frac{1701}{14}\): \[ \frac{30 \times 121}{14 \times 121} = \frac{3630}{1701} \] 2. For \(\frac{125}{243}\): - Multiply both the numerator and denominator by \(\frac{1701}{243}\): \[ \frac{125 \times 7}{243 \times 7} = \frac{875}{1701} \] ### Step 6: Add the Two Fractions Now we can add the two fractions: \[ \frac{3630}{1701} + \frac{875}{1701} = \frac{3630 + 875}{1701} = \frac{4505}{1701} \] ### Final Step: Simplify if Possible The final answer is \(\frac{4505}{1701}\). We check if this fraction can be simplified further. Since 4505 and 1701 have no common factors other than 1, this is the simplest form. ### Final Answer \[ \frac{4505}{1701} \] ---
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ICSE-FRACTIONS-Exercise 2.3
  1. Find: f. 1 (13)/(5) div 1 (5)/(7)

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  2. Simplify : a. ((4)/(7) div (36)/(49)) - (1)/(2)

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  3. Simplify : b. (5)/(9) div ((3)/(10) xx (5)/(12))

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  4. Simplify : c. (3)/(5) of ((1)/(15) xx 3 (2)/(5))

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  5. Simplify : d. (1)/(6) of (1 (1)/(9) div 7 (1)/(2) )

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  6. Simplify : e. 5 (1)/(3) xx (3)/(8) - (7)/(9) div 2 (1)/(10)

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  7. Simplify : f. (13)/(7) + 4 (4)/(5) xx (3)/(4) div (7)/(15)

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  8. Simplify : g. ((3)/(8) xx (2)/(15)) + ((4)/(9) div (32)/(27))

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  9. Simplify : ((6)/(7) div (2)/(5)) + ((5)/(9) div (27)/( 25))

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  10. Simplify : i. (1 (5)/(7) xx (7)/(10) ) - ((3)/(5) div (9)/(10))

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  11. Simplify : j. ((21)/(10) xx (2)/(14) ) - ((1)/(7) div (36)/(28))

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  12. Amit buys chocolates worth Rs. 97 (1)/(2). If one chocolate costs Rs. ...

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  13. One banana costs Rs. 5 (3)/(4). How many bananas can be bought for Rs....

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  14. A box of candies weighs 640 (1)/(2) g. If each candy weighs 45 (3)/(4)...

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  15. Suraj has to distribute 9 kg of sweets into 40 boxes. Find the quantit...

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  16. Suman covers 2 (4)/(5) km in (7)/(12) hours. a. How much time is req...

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  17. Suman covers 2 (4)/(5) km in (7)/(12) hours. b. How much will Suman ...

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  18. The product of two numbers is 3 (1)/(3). If one number is 3 (3)/(5), f...

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  19. Anjali covers 43 (1)/(2) km in 7 (1)/(4) hours and Nisha covers 27 (5)...

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  20. Kiran knits 2 (3)/(4) pullovers in 14 (2)/(3) hours and Anu knits 4 (1...

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