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A box of candies weighs 640 (1)/(2) g. I...

A box of candies weighs `640 (1)/(2)` g. If each candy weighs `45 (3)/(4)`g, how many candies are there in the box?

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To find the number of candies in the box, we need to divide the total weight of the box of candies by the weight of each candy. Let's break this down step by step. ### Step 1: Convert Mixed Numbers to Improper Fractions The weight of the box is given as \( 640 \frac{1}{2} \) grams. We need to convert this mixed number into an improper fraction. 1. Multiply the whole number (640) by the denominator (2): \[ 640 \times 2 = 1280 \] 2. Add the numerator (1) to this result: \[ 1280 + 1 = 1281 \] 3. So, \( 640 \frac{1}{2} \) can be written as: \[ \frac{1281}{2} \] ### Step 2: Convert the Weight of Each Candy to an Improper Fraction The weight of each candy is given as \( 45 \frac{3}{4} \) grams. We will convert this mixed number into an improper fraction as well. 1. Multiply the whole number (45) by the denominator (4): \[ 45 \times 4 = 180 \] 2. Add the numerator (3) to this result: \[ 180 + 3 = 183 \] 3. So, \( 45 \frac{3}{4} \) can be written as: \[ \frac{183}{4} \] ### Step 3: Set Up the Division Now we need to find the total number of candies by dividing the weight of the box by the weight of each candy: \[ \text{Number of candies} = \frac{1281/2}{183/4} \] ### Step 4: Apply the Rule for Dividing Fractions When dividing fractions, we multiply by the reciprocal of the divisor: \[ \frac{1281}{2} \div \frac{183}{4} = \frac{1281}{2} \times \frac{4}{183} \] ### Step 5: Simplify the Expression Now we can simplify this expression: \[ = \frac{1281 \times 4}{2 \times 183} \] Calculating the numerator: \[ 1281 \times 4 = 5124 \] Calculating the denominator: \[ 2 \times 183 = 366 \] So we have: \[ \frac{5124}{366} \] ### Step 6: Simplify the Fraction Now we can simplify \( \frac{5124}{366} \): 1. Divide both the numerator and the denominator by 2: \[ \frac{5124 \div 2}{366 \div 2} = \frac{2562}{183} \] ### Step 7: Perform the Division Now we can perform the division: \[ 2562 \div 183 = 14 \] This means the total number of candies is 14. ### Final Answer The total number of candies in the box is **14**. ---
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ICSE-FRACTIONS-Exercise 2.3
  1. Find: f. 1 (13)/(5) div 1 (5)/(7)

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  2. Simplify : a. ((4)/(7) div (36)/(49)) - (1)/(2)

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  3. Simplify : b. (5)/(9) div ((3)/(10) xx (5)/(12))

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  4. Simplify : c. (3)/(5) of ((1)/(15) xx 3 (2)/(5))

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  5. Simplify : d. (1)/(6) of (1 (1)/(9) div 7 (1)/(2) )

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  6. Simplify : e. 5 (1)/(3) xx (3)/(8) - (7)/(9) div 2 (1)/(10)

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  7. Simplify : f. (13)/(7) + 4 (4)/(5) xx (3)/(4) div (7)/(15)

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  8. Simplify : g. ((3)/(8) xx (2)/(15)) + ((4)/(9) div (32)/(27))

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  9. Simplify : ((6)/(7) div (2)/(5)) + ((5)/(9) div (27)/( 25))

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  10. Simplify : i. (1 (5)/(7) xx (7)/(10) ) - ((3)/(5) div (9)/(10))

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  11. Simplify : j. ((21)/(10) xx (2)/(14) ) - ((1)/(7) div (36)/(28))

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  12. Amit buys chocolates worth Rs. 97 (1)/(2). If one chocolate costs Rs. ...

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  13. One banana costs Rs. 5 (3)/(4). How many bananas can be bought for Rs....

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  14. A box of candies weighs 640 (1)/(2) g. If each candy weighs 45 (3)/(4)...

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  15. Suraj has to distribute 9 kg of sweets into 40 boxes. Find the quantit...

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  16. Suman covers 2 (4)/(5) km in (7)/(12) hours. a. How much time is req...

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  17. Suman covers 2 (4)/(5) km in (7)/(12) hours. b. How much will Suman ...

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  18. The product of two numbers is 3 (1)/(3). If one number is 3 (3)/(5), f...

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  19. Anjali covers 43 (1)/(2) km in 7 (1)/(4) hours and Nisha covers 27 (5)...

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  20. Kiran knits 2 (3)/(4) pullovers in 14 (2)/(3) hours and Anu knits 4 (1...

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