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Anjali covers 43 (1)/(2) km in 7 (1)/(4)...

Anjali covers `43 (1)/(2)` km in `7 (1)/(4)` hours and Nisha covers `27 (5)/(8)` km in `4 (1)/(4) `hours Who walks faster. Who walks faster and by how much?

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To determine who walks faster between Anjali and Nisha, we need to calculate their speeds using the formula: **Speed = Distance / Time** ### Step 1: Convert Mixed Numbers to Improper Fractions **For Anjali:** - Distance: \(43 \frac{1}{2} = \frac{87}{2}\) km - Calculation: \(43 \times 2 + 1 = 86 + 1 = 87\), so \( \frac{87}{2} \) km. - Time: \(7 \frac{1}{4} = \frac{29}{4}\) hours - Calculation: \(7 \times 4 + 1 = 28 + 1 = 29\), so \( \frac{29}{4} \) hours. **For Nisha:** - Distance: \(27 \frac{5}{8} = \frac{221}{8}\) km - Calculation: \(27 \times 8 + 5 = 216 + 5 = 221\), so \( \frac{221}{8} \) km. - Time: \(4 \frac{1}{4} = \frac{17}{4}\) hours - Calculation: \(4 \times 4 + 1 = 16 + 1 = 17\), so \( \frac{17}{4} \) hours. ### Step 2: Calculate Speeds **For Anjali:** - Speed = Distance / Time = \( \frac{87/2}{29/4} \) - This simplifies to \( \frac{87}{2} \times \frac{4}{29} = \frac{348}{58} = \frac{174}{29} \approx 6\) km/h. **For Nisha:** - Speed = Distance / Time = \( \frac{221/8}{17/4} \) - This simplifies to \( \frac{221}{8} \times \frac{4}{17} = \frac{884}{136} = \frac{221}{34} \approx 6.5\) km/h. ### Step 3: Compare Speeds - Anjali's speed: \(6\) km/h - Nisha's speed: \(6.5\) km/h ### Step 4: Determine Who Walks Faster and By How Much - Nisha walks faster than Anjali. - To find the difference: \(6.5 - 6 = 0.5\) km/h. ### Final Answer: Nisha walks faster than Anjali by \(0.5\) km/h. ---
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ICSE-FRACTIONS-Exercise 2.3
  1. Find: f. 1 (13)/(5) div 1 (5)/(7)

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  2. Simplify : a. ((4)/(7) div (36)/(49)) - (1)/(2)

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  3. Simplify : b. (5)/(9) div ((3)/(10) xx (5)/(12))

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  4. Simplify : c. (3)/(5) of ((1)/(15) xx 3 (2)/(5))

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  5. Simplify : d. (1)/(6) of (1 (1)/(9) div 7 (1)/(2) )

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  6. Simplify : e. 5 (1)/(3) xx (3)/(8) - (7)/(9) div 2 (1)/(10)

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  7. Simplify : f. (13)/(7) + 4 (4)/(5) xx (3)/(4) div (7)/(15)

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  8. Simplify : g. ((3)/(8) xx (2)/(15)) + ((4)/(9) div (32)/(27))

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  9. Simplify : ((6)/(7) div (2)/(5)) + ((5)/(9) div (27)/( 25))

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  10. Simplify : i. (1 (5)/(7) xx (7)/(10) ) - ((3)/(5) div (9)/(10))

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  11. Simplify : j. ((21)/(10) xx (2)/(14) ) - ((1)/(7) div (36)/(28))

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  12. Amit buys chocolates worth Rs. 97 (1)/(2). If one chocolate costs Rs. ...

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  13. One banana costs Rs. 5 (3)/(4). How many bananas can be bought for Rs....

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  14. A box of candies weighs 640 (1)/(2) g. If each candy weighs 45 (3)/(4)...

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  15. Suraj has to distribute 9 kg of sweets into 40 boxes. Find the quantit...

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  16. Suman covers 2 (4)/(5) km in (7)/(12) hours. a. How much time is req...

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  17. Suman covers 2 (4)/(5) km in (7)/(12) hours. b. How much will Suman ...

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  18. The product of two numbers is 3 (1)/(3). If one number is 3 (3)/(5), f...

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  19. Anjali covers 43 (1)/(2) km in 7 (1)/(4) hours and Nisha covers 27 (5)...

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  20. Kiran knits 2 (3)/(4) pullovers in 14 (2)/(3) hours and Anu knits 4 (1...

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