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`2pqr^2-p^2q+pq and 3p^2q-ab+2`

If two positive integers a and b are expressible in the form a =pq^2 and b=p^3q , p and q being prime numbers, then HCF (a,b) is a)pq b)p^3q^3 c)p^3q^2 d)p^2q^2

What should be subtracted from 2p^2+3q^2 +6pq to get p^2-q^2 ?

If p and q are positive, p^2 + q^2 = 16 , and p^2 - q^2 = 8 , then q =

Add the following. (i) ab-bc, bc-ca,ca-ab (ii) a-b+ab,b-c+bc,c-a+ac (iii) 2p^2q^2-3pq+4,5+7pq-3p^2q^2 (iv) l^2+m^2,m^2+n^2,n^2+l^2,2lm+2mn+2nl

The number of non-negative integers 'n' satisfying n^2 = p+q and n^3 = p^2+ q^2 where p and q are integers

Find the value of 2p^2q-3pq^2+2p-3p+1 when p=3,q=-3

Find the excess of 4p^(2)-2pq +3q^(2) over 2p^(2)-pq +4q^(2) .

Multiply : 5p^(2) + 25pq + 4q^(2) by 2p^(2) - 2pq + 3q^(2)

If two positive integers a and b are expressible in the form a=p q^2 and b=p^3q ; p ,\ q being prime numbers, then LCM (a ,\ b) is (a) p q (b) p^3q^3 (c) p^3q^2 (d) p^2q^2

Subtract : 3p^(3)-5p^(2)q from q^(2)+p^(2)q-4p^(3)