Find the perimeter of an isosceles triangle with base 14 cm and equal sides 10 cm each.

Answer

To find the perimeter of an isosceles triangle with a base of 14 cm and equal sides of 10 cm each, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the sides of the triangle**:
- The base (a) of the isosceles triangle is given as 14 cm.
- The lengths of the equal sides (b and c) are both given as 10 cm each.

2. **Write the formula for the perimeter of a triangle**:
- The perimeter (P) of a triangle is calculated by adding the lengths of all its sides:
\[ P = a + b + c \]

3. **Substitute the values into the formula**:
- Here, we substitute the values we have:
\[ P = 14 \, \text{cm} + 10 \, \text{cm} + 10 \, \text{cm} \]

4. **Perform the addition**:
- First, add the lengths of the equal sides:
\[ 10 \, \text{cm} + 10 \, \text{cm} = 20 \, \text{cm} \]
- Now add the base:
\[ 20 \, \text{cm} + 14 \, \text{cm} = 34 \, \text{cm} \]

5. **State the final answer**:
- Therefore, the perimeter of the isosceles triangle is:
\[ P = 34 \, \text{cm} \]