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Displacement is a scalar quantity...

Displacement is a scalar quantity

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STATEMENT - 1 : Distance is a vector quantity and displacement is a scalar quantity. STATEMENT - 2 : A person makes a round - trip journey, finishing where she started. The displacement for the trip is 0 and the distance is some nonzero value. STATEMENT - 3 : A person starts at position A and finishes at position B. The distance for the trip is the length of the segment measured from A to B.

Dipole moment is a scalar quantity and is given by m=q xx r .

(A):Displacement of a body is the signed sum of the area under velocity-time graph. (R ):Displacement is a vector quantity.

Discuss whether or not , angular displacement is a vector quantity ?

Which of the following statements is incorrect? a) Path length is a scalar quantity whereas displacement is a vector quantity. b) The displacement depends only on the end points whereas path length depends on the actual path followed. c) The path length is always positive whereas displacement can be positive, negative and zero. d) The path length is always positive whereas displacement can be positive, negative and zero.

Angular displacement is a vector quantity for __________ angles. (very small/even large)

Assertion - small displacement is a vector quantity. Reason Pressure and surface tension are also vector quanities.

Distance is a scalar quantity. Displacement is a vector quqntity. The magnitude of displacement is always less than or equal to distance. For a moving body displacement can be zero but distance cannot be zero. Same concept is applicable regarding velocity and speed. Acceleration is the rate of change of velocity. If acceleration is constant, then equations of kinematics are applicable for one dimensional motion under the gravity in which air resistance is considered, then the value of acceleration depends on the density of medium. Each motion is measured with respect of frame of reference. Relative velocity may be greater // smaller to the individual velocities. A person is going 40 m north, 30m east and then 30sqrt(2) m southwest. The net displacement will be

Assertion: Distance is a actual length of the path but displacement is a shortest distance between initial and final position. Reason: Distance is a scalar quantity and it is always positive but displacement is a vector quantity. It may be positive, negative or zero.

Assertion: Distance is a scalar quantity. Reason: Distance is the length of path traversed.