Weight of a person on the Earth depends on the gravitational force exerted by the Earth.

A satellite revolves around earth under the gravitational force exerted upon it the earth. Does it perform any work ?

Name the following. Gravitational force exerted by the Earth on an object .

The gravitational force exerted by the Sun on the Moon is about twice as great as the gravitational force exerted by the earth on the Moon, but still Moon is not escaping from the gravitational influence of the earth. Mark the option which correctly explains the above system.

Let F_1 be the magnitude of the gravitational force exerted on the Sun by Earth and F_2 be the magnitude of the force exerted on Earth by the Sun. Then:

Write the formula to find the magnitude of the gravitational force between the Earth and an object on the surface of the Earth.

A uniform thin rod of mass m and length R is placed normally on surface of earth as shown. The mass of earth is M and its radius R . Then the magnitude of gravitational force exerted by earth on the rod is

The centripetal force on a satellite orbiting round the earth and the gravitational force of earth acting on the satellite both equal F. The net force on the satellite is

It is known that the time of revolution T of a satellite around the earth depends on the universal gravitational constant G, the mass of the earth M, and the radius of the circular orbit R. Obtain an expression for T using dimensional analysis.

A body of weight 72 N moves from the surface of earth at a height half of the radius of earth , then geavitational force exerted on it will be

A uniform thin rod of mass m and length R is placed normally on surface of earth as shown. The mass of earth is M and its radius is R. If the magnitude of gravitational force exerted by earth on the rod is (etaGMm)/(12R^(2)) then eta is