Two bulbs, when connected in series, are brighter than a single bulb.

Two inductances connected in parallel are equivalent to a single inductance of 1.5H and when connected in series are equivalent to a single inductance of 8 H. The difference in their inductance is

STATEMENT-1 : In a chain of 50 bulbs connected in series, one bulb is taken out remaining 49 bulbs are again connected in series across the same supply then light gets decreased in the room. and STATEMENT-2 : More resistance in the circuit means lesser current drawn source.

3 identical bulbs are connected in series and these together dissipate a power P . If now the bulbs are connected in parallel, then the power dissipated will be

n identical bulbs are connected in series and illuminated by a power supply . One of the bulbs gets fused. The fused bulb is removed , and the remaining bulbs are again illuminated by the same power supply. Find the fractional change in the illuminated of (a) all the bulbs and (b) one bulb.

Assertion : Two 60 W bulbs are first connected in series and then in parallel with same battery. Total power produced in second case will become four times. Rated voltage is same for two bulbs. Reason : In series total power produced will be 30 W and in parallel 120 W.

Two bulbs are working in parallel order. Bulb A is brighter than bulb B . If R_(A) and R_(B) are their resistance respectively then

Two bulbs when connected in parallel to a source take 60 W each, the power consumed, when they are connected in series with the same source is

Two bulbs when connected in parallel to a source take 100 W each. The total power consumed when they are connected in series with the same source is

40 electric bulb are connected in series across a 220 V supply. After one bulb is fused the remaining 39 are connected again in series across the same supply. The illumination will be

A capacitor and a bulb are connected in series with a source of alternating emf. If a dielectric slab is inserted between the plates of the capacitor, then