Find the volume of 900 g of cooking oil whose density is `0.9 "g/cm"^3`. Give the answer in litres.

Answer

To find the volume of 900 g of cooking oil with a density of 0.9 g/cm³, we can follow these steps:

### Step 1: Understand the relationship between mass, density, and volume.
We know that the formula relating mass (m), density (ρ), and volume (V) is:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
From this formula, we can rearrange it to find the volume:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]

### Step 2: Substitute the given values into the formula.
We are given:
- Mass (m) = 900 g
- Density (ρ) = 0.9 g/cm³

Now, substituting these values into the volume formula:
\[ V = \frac{900 \text{ g}}{0.9 \text{ g/cm}^3} \]

### Step 3: Perform the division.
Now, we calculate the volume:
\[ V = \frac{900}{0.9} \]
To simplify this, we can multiply both the numerator and the denominator by 10 to eliminate the decimal:
\[ V = \frac{9000}{9} = 1000 \text{ cm}^3 \]

### Step 4: Convert the volume from cm³ to liters.
We know that:
1 liter = 1000 cm³

Thus, to convert 1000 cm³ to liters:
\[ \text{Volume in liters} = \frac{1000 \text{ cm}^3}{1000} = 1 \text{ liter} \]

### Final Answer:
The volume of 900 g of cooking oil is **1 liter**.

---