An empty beaker weighs 100 g. A volume of 75 mL of salt solution is taken and weighed. It is found to be 190 g. What is the density of the salt solution in `"g/cm"^3` and also in `"kg/m"^3`?

Answer

To find the density of the salt solution, we can follow these steps:

### Step 1: Determine the mass of the salt solution
The total weight of the beaker with the salt solution is given as 190 g, and the weight of the empty beaker is 100 g. To find the mass of the salt solution alone, we subtract the weight of the empty beaker from the total weight.

\[ \text{Mass of salt solution} = \text{Total weight} - \text{Weight of empty beaker} \]
\[ \text{Mass of salt solution} = 190 \, \text{g} - 100 \, \text{g} = 90 \, \text{g} \]

### Step 2: Identify the volume of the salt solution
The volume of the salt solution is given as 75 mL. Since 1 mL is equivalent to 1 cm³, we can state that:

\[ \text{Volume of salt solution} = 75 \, \text{mL} = 75 \, \text{cm}^3 \]

### Step 3: Calculate the density of the salt solution
Density is defined as mass per unit volume. We can use the mass of the salt solution and its volume to calculate the density.

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
\[ \text{Density} = \frac{90 \, \text{g}}{75 \, \text{cm}^3} = 1.2 \, \text{g/cm}^3 \]

### Step 4: Convert the density to kg/m³
To convert the density from g/cm³ to kg/m³, we can use the conversion factor where 1 g/cm³ is equal to 1000 kg/m³.

\[ \text{Density in kg/m}^3 = 1.2 \, \text{g/cm}^3 \times 1000 \, \text{kg/m}^3 = 1200 \, \text{kg/m}^3 \]

### Final Results
- The density of the salt solution is **1.2 g/cm³**.
- The density of the salt solution is also **1200 kg/m³**.

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