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Force exerted on unit area of a surface ...

Force exerted on unit area of a surface by the weight of the air above it

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End A of the bar AB in figure rests on a frictionless horizontal surface and end B is hinged. A horizontal force vecF of magnitude 120 N is exerted on end A . You can ignore the weight of the bar. What is the net force exerted by the bar on the hinge at B ?

Consider a small surface area of 1 mm^2 at the top of a mercury drop of radius 4.0 mm. Find the force exerted on this area (a) by the air above it (b) by the mercury below it and (c) by the mercury surface in contact with it. Atmospheric pressure =1.0xx10^5Pa and surface tension of mercury =0.465Nm^-1. Neglect the effect of gravity. Assume all numbers to be exact.

Pressure is determined as force per unit area of the surface. The SI unit of pressure, pascal is as shown below: 1 Pa=N m^(-2) If the mass of air at sea level is 1034 g cm^(-2) , calculate the pressure in pascal.

Pressure is determined as force per unit area of the surface. The SI unit of pressure, pascal is as shown below : 1 Pa = 1 Nm^(-2) . If mass of air at sea level is 1034 g cm^(-2) , calculate the pressure in pascal.

A man of mass m is standing in an elevator moving downward with an acceleration (g)/(4) . The force exerted by the bottom surface of the elevator on the man will be

"When a person walks on a rough surface the frictional force exerted by the surface on the person is opposite to the direction of his motion". Is it true or false ?

Find the force exerted by the water on a 2m^2 plane surface of a large stone placed at the bottom of a sea 500 m deep. Does the force depend on the orientation of the surface? Neglect the size of the stone in comparison to the depth of the sea.

Let F_1 be the magnitude of the gravitational force exerted on the Sun by Earth and F_2 be the magnitude of the force exerted on Earth by the Sun. Then:

When a person walks on a rough surface, the frictional force exerted by surface on the person is opposite to the direction of his motion. It is the force exerted by the road on the person that causes the motion.

A wind with speed 40m//s blows parallel to the roof of a house. The area of the roof is 250 m^(2) . Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (P_(air) = 1.2 kg//m^(3))