The moment of a force of 50 N about a point is 5 Nm. Find the perpendicular distance of force from that point.

Answer

To solve the problem, we need to find the perpendicular distance of a force from a point given the moment (torque) of the force and the magnitude of the force itself.

### Step-by-Step Solution:

1. **Understand the relationship**: The moment (torque) of a force about a point is given by the formula:
\[ \text{Moment} = \text{Force} \times \text{Perpendicular Distance} \]
This can be expressed as:
\[ \tau = F \times r \]
where \( \tau \) is the moment (in Nm), \( F \) is the force (in N), and \( r \) is the perpendicular distance (in m).

2. **Identify the given values**: From the problem, we know:
- Moment (τ) = 5 Nm
- Force (F) = 50 N

3. **Rearrange the formula to solve for r**: We need to find the perpendicular distance \( r \). Rearranging the formula gives us:
\[ r = \frac{\tau}{F} \]

4. **Substitute the known values into the equation**:
\[ r = \frac{5 \, \text{Nm}}{50 \, \text{N}} \]

5. **Calculate the value of r**:
\[ r = \frac{5}{50} = 0.1 \, \text{m} \]

6. **Conclusion**: The perpendicular distance of the force from that point is:
\[ r = 0.1 \, \text{meters} \]

### Final Answer:
The perpendicular distance of the force from that point is **0.1 meters**.