tan(A±B) & cot(A±B) Formulae

Prove that: (tan(A+B))/(cot(A-B))=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

(sin^(2)A-sin^(2)B)/(sin A cos A-sin B cos B) is equal to (a) sin A cos A-sin B cos Btan(A-B)(b)tan(A+B)cot(A-B)(d)cot(A+B)

frac(tan A + tan B)(cot A + cot B) is equal to

If tan A - tan B = x and cot B - cot A =y , then what is cot ( A -B) equal to ?

tan(A+B)=p,tan(A-B)=qthen cot2B=

If (x)/(y)=(cos A)/(cos B)then(x tan A+y tan B)/(x+y)=cot(A+B)/(2)(b)cot(A-B)/(2)tan(A-B)/(2) (d) tan(A+B)/(2)

If tan A = cot B , prove that A + B = 90^(@) .

In triangle ABC, if |[1,1,1], [cot (A/2), cot(B/2), cot(C/2)], [tan(B/2)+tan(C/2), tan(C/2)+ tan(A/2), tan(A/2)+ tan(B/2)]| then the triangle must be (A) Equilateral (B) Isoceless (C) Right Angle (D) none of these

(cot (A + B)) / (2) * (tan (AB)) / (2) = (a) (a + b) / (ab) (b)