If a curve passes through the origin and the slope of the tangent to it at any point (x, y) is `(x^(2)-4x+y+8)/(x-2)`, then this curve also passes through the point:

If a curve passes through the point (1,-2) and has slope of the tangent at any point (x, y) on it as (x^2_2y)/x , then the curve also passes through the point - (a) (sqrt3,0) (b) (-1,2) (c) (-sqrt2,1) (d) (3,0)

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point

Curve passing through (0,0) and slope of tangent to any point (x,y) is (x^2-4x+y+8)/(x-2) , then curve also passes through

A curve passes through the point (2,0) and the slope of the tangent at any point (x, y) is x^(2)-2x for all values of x then 6y_(max) is equal to

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (x,y) is equal to the sum of the coordinates of the point.

A curve passes through the point (3,-4) and the slope of.the is the tangent to the curve at any point (x,y) is (-(x)/(y)) .find the equation of the curve.

Find the equation of a curve, passes through (-2,3) at which the slope of tangent at any point (x,y) is (2x)/(y^(2)) .

Determine the equation of the curve passing through the origin,the slope of the tangent of which at any point (x,y) is (x+1)/(y+1)

Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is -(x)/(y) .

The slope of the tangent to the curve at any point is equal to y + 2x. Find the equation of the curve passing through the origin .