The ratio of the sum of m and n terms of an A.P. is `m^(2)` :`n^(2)`. Show that the ratio `m^(th)` and `n^(th)` term is `(2m-1) : (2n-1).`

The ratio of the sum of m and n terms of an A.P. is m^(2) :n^(2) . Show that the ratio mth and nth term is (2n-1) : (2n-1).

If the ratio of the sums of m and n terms of A.P. is m^(2):n^(2) , then the ratio of its m^(th) and n^(th) terms is given by

The ratio of the sums of m terms and n terms of an A.P. is m^(2) : n^(2). Prove that the ratio of their mth and nth term will be (2m - 1) : (2n-1).

If the ratio of sum of m terms of an AP to the sum of n terms of the same AP is (m^(2))/(n^(2)) .Then prove that the ratio of its mth and nth terms is 2m-1:2n-1.

The ratio of the sum of n terms of two A.Ps is (7n+1):(4n+27). Find the ratio of their m^(th) terms.

If the sum of first n terms of an A.P. is 3n^(2)-2n , then its 19th term is

if the sum of m terms of an A.P is to the sum of n terms as m^(2) to n^(2) show that the mth term is to the n th term as 2m-1 to 2n-1

If the sum of n terms of an A.P is 2n+3n^(2) , find the r^(th) term