`dy/dx` of `(x^y)(y^x)=1`

Find dy/dx if y = x^(1/x)

Find (dy)/(dx) if "y=(x+1)/(x)

The general solution of the differential equation (dy)/(dx) +x (x+y)=x (x+y) ^(3)-1 is:

Solve (dy)/(dx) = (x+y+1)/(x+y-1) when x = (2)/(3), y = (1)/(3)

Solve the differential equation : dy / dx = (x+y+1)/(x+y-1 )

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

(dy)/(dx)=(x+y)ln(x+y)-1

Find dy/dx if : x^sin y +y^cos x =1

Solve: dy/dx+x(x+y)=x^3(x+y)^3-1