`(sqrt(2) + 1)^(6) - (2sqrt(2) -1)^(6)` is equal to

(sqrt(2) + 1)^(6) - (sqrt(2) -1)^(6) is equal to

Evalute: (sqrt(2)+1)^(6) + ( sqrt(2) - 1)^(6)

Given that: sqrt(3) = 1.732, (sqrt(6) + sqrt(2)) / (sqrt(6)-sqrt(2)) is equal to:

Evaluate using binomial theorem: (i) (sqrt(2)+1)^(6) +(sqrt(2)-1)^(6) (ii) (sqrt(5)+sqrt(2))^(4)-(sqrt(5)-sqrt(2))^(4)

(x+sqrt(x^(2)-1))^(6)+(x-sqrt(x^(2)-1))^(6)

2(sqrt(2)+sqrt(6)) The fraction (2(sqrt(2)+sqrt(6)))/(3(sqrt(2+sqrt(3)))) is equal to (A) (2sqrt(2))/(3)( B) 1(C)(2sqrt(3))/(3)(D)(4)/(3)