`sec^(-1)x + cosec^(-1)x = (pi)/2`

The range of function f(x)=cot^(-1)x+sec^(-1)x+ cosec^(-1)x is (A) [(pi)/(2), pi)uu(pi, (3 pi)/(2)] (B) ((pi)/(2), (3 pi)/(4)] uu [(5 pi)/(4), (3 pi)/(2)) (C) ((pi)/(2), pi)uu(pi ,(3 pi)/(2)) (D) ((pi)/(2), (3 pi)/(2))

If cosec^(-1)x+cosec^(-1)y+cosec^(-1)z=-(3pi)/(2),then x/y+y/z+z/x=

sin(sec^(-1)x+"cosec"^(-1)x)

If sec^(-1)(2) +"cosec"^(-1) (y) = pi/2 , then find y .

Sove sec^(-1) x gt cosec^(-1) x

The area of the closed region bounded by y=sec^(-1)x, y ="cosec"^(-1)x and the line x-1=0 is

Prove that : cos(sec^(-1) x+ cosec^(-1) x) =0, |x| ge 1

f(x) and and g(x) are identical or not ? f(x)=Sec^(-1)x+Cosec^(-1)x,g(x)=pi/2

If sec^(-1)(x) +"cosec"^(-1) (1/3) = pi/2 , then find x .