Figure shows two blocks in contact sliding down an inclined surface of inclination `30^(@)`. The friction coefficient between the block of mass 2.0 kg and the incline is `mu_(1) =0.20`.The friction coefficient between the block of mass `4.0kg` and the incline is `mu _(2) =0.30`. Find the acceleration of `2.0kg` block. `(g = 10m//s^(2))`

Figure shown two blocks in contact sliding down an inclined surfase of inclination 30^(@) . The friction coefficient between the block of mass 4.0kg and the incline is mu _(2) =0.30 . Find the acceleration of 2.0kg block. (g = 10m//s^(2))

Figure shown two blocks in contact sliding down an inclined surface of inclination 30^(@) . The block of mass 2 kg and the incline is mu_(1) = 0.20 and the incline is mu_(2) = 0.30 .Find the acceleration of 2.0 kg block g = 10 ms^(-2)

Figure shows two blocks in contact placed on an incline of angle theta = 30^(@) . The coefficient of friction between the block of mass 4 kg and the incline is m1, and that between 2 kg block and incline is mu_(2) . Find the acceleration of the blocks and the contact force between them if – (a) mu_(1) = 0.5 , mu_(2) = 0.8 (b) mu_(1) = 0.8 , mu_(2) = 0.5 (c) mu_(1) = 0.6 , mu_(2) = 0.1 " " [ Take g = 10m//s^(2) ]

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is

A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .

A block of mass 10 kg is sliding on a surface inclined at 30^(@) with horizontal . If coefficient of friction between the block and the surface is 0.5 , find acceleration produced in the block . Take g = 9.8 m //^(2) .

A block of mass 10 kg is kept on a fixed rough (mu=0.8) inclined plane of angle of inclination 30^(@) . The frictional force acting on the block is