Home
Class 12
CHEMISTRY
An element (at. mass = 60) having face c...

An element (at. mass = 60) having face centred cubic unit cell has a density of 6.23g `cm^(-3)`. What is the edge length of the unit cell? (Avogadro's constant = `6.023 xx 10^(23) mol^(-1)`)

Text Solution

Verified by Experts

The correct Answer is:
400 pm
M=60, Z = 4 for fcc unit cell, d=6.23 g `cm^(-3)`, `N_A = 6.023 xx 10^(23) mol^(-1), d = (ZM)/(Ν_Α xx a^3)`
`a^3=(4 xx 60)/(6.023 xx 10^(23) xx 6.23) cm^3 = 6.396 xx 10^(-23) cm^3`,
`a = 4 xx 10^(-8)` cm = 400 pm
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    KALYANI PUBLICATION|Exercise FOLLOW UP PROBLEMS(Type III. Calculation of Avogadro.s Number)|2 Videos

  • SOLID STATE

    KALYANI PUBLICATION|Exercise FOLLOW UP PROBLEMS(Type IV. Calculation of Atomic Mass and Number of Atoms in a given mass.)|4 Videos

  • SOLID STATE

    KALYANI PUBLICATION|Exercise FOLLOW UP PROBLEMS(Type 1. Calculation of Density of unit cell.)|2 Videos

  • POLYMERS

    KALYANI PUBLICATION|Exercise EXERCISE (PART-II (DESCRIPTIVE QUESTIONS )) ( SHORT ANSWER QUESTIONS|5 Videos

  • SURFACE CHEMISTRY

    KALYANI PUBLICATION|Exercise EXERCISE (PART-II ( DESCRIPTIVE QUESTIONS )) (VERY SHORT ANSWER QUESTIONS)|31 Videos