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Determine the type of cubic lattice to which the iron crystal belongs if its unit cell has an edge length of 286 pm and the density of iron crystals is 7.86g `cm^(-3)`.

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The correct Answer is:
bcc
a=286 pm, d=7.86g `cm^(-3)`, `N_A = 6.023 xx 10^(23)`,
For iron M = 56 g `mol^(-1)`, `d = (ZM)/(N_A xx a^3)` or `Z= (d xx N_A xx a^3)/(M)= (7.86 xx 6.023 xx 10^(23) xx (286 xx 10^(-10))^3)/(56) = 1.98 ~~ 2`
Since Z= 2, iron has bcc structure.
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