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A bcc element (atomic mass 65) has cell ...

A bcc element (atomic mass 65) has cell edge of 420 pm. Calculate its density in `g cm^(-3)` .

Text Solution

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Atomic mass of element = 65
Edge length , a = 420 pm = `420 xx 10^(-10) cm`
Number of atoms per unit cell = 2 (for bcc structure)
Density of unit cell , (d) `=(Zxx M)/(N_A xx a^3 xx 10^(-30)) g cm^(-3)`
`= (2 xx 65 g "mol"^(-1))/( 6.02 xx 10^(23) "mol"^(-1) xx (420)^3 xx 10^(-30)) cm^3`
` = 2.914 g cm^(-3)`
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