Home
Class 6
MATHS
Solve the following problems. Veena ha...

Solve the following problems.
Veena has some beads. She wants to make necklaces with an equal number of beads in each. If she makes necklaces of 16, 24 or 40 beads, there is no bead left over. What is the least number of beads she must have ?

Text Solution

AI Generated Solution

To find the least number of beads Veena must have, we need to determine the least common multiple (LCM) of the numbers 16, 24, and 40. Here’s how to do it step by step: ### Step 1: Find the prime factorization of each number - **16**: The prime factorization of 16 is \(2^4\). - **24**: The prime factorization of 24 is \(2^3 \times 3^1\). - **40**: The prime factorization of 40 is \(2^3 \times 5^1\). ### Step 2: Identify the highest power of each prime factor ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL CONSTRUCTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise QUESTION BANK |7 Videos
  • INTEGERS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise QUESTION BANK|23 Videos

Similar Questions

Explore conceptually related problems

When Seeta made necklaces of either 16 beads,20 beads or 36 beads,not a single bead was left over.What could be the least number of beads Seeta had? (a) 700 (b) 720 (c) 750 (d) 780

Geeta have 50 red beads, 100 white beads and 120 blue beads. She wants to make similar bracelets so that she can use all beads of each colour. What is the least number of similar bracelets she can make?

Solve the following problems. On the playground, if the children are made to stand for drill either 20 to a row or 25 to a row, all rows are complete and no child is left out. What must be the least number of children in that school.

The number of ways in which 5 beads of different colours can be made into a necklace is

Geeta have 50 red beads, 100 white beads and 120 blue beads. She wants to make similar bracelets so that she can use all beads of each colour. Find the LCM for given white beads and blue beads.

Find the number of ways in which 12 different beads can be arranged to form a necklace.

There are n necklaces such that the first necklace contains 5 beads, the second contains 7 beads and, in general the ith necklace contains i beads more than the number of beads in (i-1)th necklace. Find the total number of beads is all the n necklaces.

Find the number of ways, in which 12 different beads can be arranged to form a necklace.

I have a certain number of beads which lie between 600 and 900. If 2 beads are taken away the remainder can be equally divided among 3, 4, 5, 6, 7, or 12 boys. The numbere of beads I have