Silver metal crystallizes with a face centred cubic lattice. The length of the unit cell is found to be `4.077 xx 10^(-8)` cm. Calculate atomic radius and density of silver. (Atomic mass of Ag = 108 u, `N_A = 6.02 xx 10^(23) mol^(-1)`)

Explanation

To solve the problem step by step, we will calculate the atomic radius and the density of silver metal crystallizing in a face-centered cubic (FCC) lattice.

### Given Data:
- Length of unit cell (a) = \(4.077 \times 10^{-8}\) cm
- Atomic mass of silver (Ag) = 108 g/mol
- Avogadro's number (\(N_A\)) = \(6.02 \times 10^{23}\) mol\(^{-1}\)

### Step 1: Calculate the Atomic Radius (R)
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