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The edge lengths of the unit cells in te...

The edge lengths of the unit cells in terms of the radius of spheres constituting fcc, bcc and simple cubic unit cell are respectively

A

`2sqrt2 r, (4r)/(sqrt3), 2r`

B

`(4r)/(sqrt3), 2sqrt2 r, 2r`

C

`2r, 2sqrt2 r, (4r)/(sqrt3)`

D

`2r, (4r)/(sqrt3), 2sqrt2 r`

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To find the edge lengths of the unit cells in terms of the radius of the spheres constituting face-centered cubic (FCC), body-centered cubic (BCC), and simple cubic unit cells, we can derive the relationships step by step. ### Step 1: Face-Centered Cubic (FCC) 1. In an FCC unit cell, atoms are located at each corner and the centers of each face. 2. The face diagonal of the cube can be represented as: \[ \text{Face diagonal} = \sqrt{2} \cdot a \] where \( a \) is the edge length of the cube. 3. The face diagonal also equals the sum of the diameters of the two atoms along the diagonal: \[ \text{Face diagonal} = 4r \] where \( r \) is the radius of the atom. 4. Setting these equal gives: \[ \sqrt{2} \cdot a = 4r \] 5. Solving for \( a \): \[ a = \frac{4r}{\sqrt{2}} = 2\sqrt{2}r \] ### Step 2: Body-Centered Cubic (BCC) 1. In a BCC unit cell, atoms are located at each corner and one atom is at the center of the cube. 2. The body diagonal of the cube can be represented as: \[ \text{Body diagonal} = \sqrt{3} \cdot a \] 3. The body diagonal also equals the sum of the diameters of the two corner atoms and the center atom: \[ \text{Body diagonal} = 4r \] 4. Setting these equal gives: \[ \sqrt{3} \cdot a = 4r \] 5. Solving for \( a \): \[ a = \frac{4r}{\sqrt{3}} \] ### Step 3: Simple Cubic (SC) 1. In a simple cubic unit cell, atoms are located only at the corners of the cube. 2. The edge length \( a \) is equal to twice the radius of the atom because there are two radii along the edge: \[ a = 2r \] ### Summary of Results - For FCC: \( a = 2\sqrt{2}r \) - For BCC: \( a = \frac{4r}{\sqrt{3}} \) - For Simple Cubic: \( a = 2r \) ### Final Answer The edge lengths of the unit cells in terms of the radius of spheres constituting FCC, BCC, and simple cubic unit cell are respectively: 1. FCC: \( 2\sqrt{2}r \) 2. BCC: \( \frac{4r}{\sqrt{3}} \) 3. Simple Cubic: \( 2r \)

To find the edge lengths of the unit cells in terms of the radius of the spheres constituting face-centered cubic (FCC), body-centered cubic (BCC), and simple cubic unit cells, we can derive the relationships step by step. ### Step 1: Face-Centered Cubic (FCC) 1. In an FCC unit cell, atoms are located at each corner and the centers of each face. 2. The face diagonal of the cube can be represented as: \[ \text{Face diagonal} = \sqrt{2} \cdot a \] ...
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ICSE-SOLID STATE-EXERCISE(PART-I OBJECTIVE QUESTIONS)
  1. Which of the following statements is not true

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  2. Which of the following is not true about the ionic solids?

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  3. A ferromagnetic substance becomes the permanent magnet when it is plac...

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  4. The correct order of the packing efficiency in different types of unit...

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  5. Which of the following defects is also known as dislocation defect?

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  6. In the cubic close packing, the unit cell has

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  7. The edge lengths of the unit cells in terms of the radius of spheres c...

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  8. Which of the following represents correct order of conductivity in sol...

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  9. Correct the following statement by changing the underlined part of the...

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  10. Correct the following statement by changing the underlined part of the...

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  11. Correct the following statement by changing the underlined part of the...

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  12. Correct the following statement by changing the underlined part of the...

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  13. Correct the following statement by changing the underlined part of the...

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  14. Correct the following statement by changing the underlined part of the...

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  15. Correct the following statement by changing the underlined part of the...

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  16. Correct the following statement by changing the underlined part of the...

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  17. Correct the following statement by changing the underlined part of the...

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  18. Correct the following statement by changing the underlined part of the...

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  19. Match the following :

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  20. Match the following :

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