Show that the density of a cubic crystal is given by the expression:
`d = (ZM)/(a^3 N_A)`
where Z is the number of atoms/molecules/ions present per unit cell, M is molecular weight, `N_A` is Avogadro's number and `a^3` is the volume of unit cell.

For a crystal of diamond, state : The number of carbon atoms present per unit cell.

What is the number of atoms per unit cell in a body centred cubic structure ?

What is the number of atoms per unit cell in a body centred cubic structure ?

In sc, bcc and fcc the ratio of number of atoms per unit cell is given by

The number of atoms present per unit cell in simple, fcc and bcc are ………, ……….., and …………, respectively.

The number of atoms present per unit cell in simple, fcc and bcc are ………, ……….., and …………, respectively.

The number of atoms present per unit cell in simple, fcc and bcc are ………, ……….., and …………, respectively.

In a face centred cubic (f.c.c.) arrangement, the number of atoms per unit cell is

What is the number of atoms in a unit cell of a face-centred cubic crystal ?

Density of a unit cell is respresented as rho = (" Effective no. of atoms (s)" xx "Mass of a unit cell ")/("Volume of a unit cell ")=(Z.M)/(N_(A).a^(3)) where , Z = effective no . of atoms(s) or ion (s) per unit cell. M= At . mass// formula N_(A) = Avogadro' s no . rArr 6.0323 xx 10^(23) a= edge length of unit cell Silver crystallizes in a fcc lattice and has a density of 10.6 g//cm^(3) . What is the length of a edge of the unit cell ?