On addition of small amount of `KMnO_(4)` to concentrated `H_(2)SO_(4)`, a green oily compound is obtained which is highly explosive in nature. Identify the compound from the following

Options

A. `Mn_(2)O_(7)`
B. `MnO_(7)`
C. `MnSO_(4)`
D. `Mn_(2)O_(3)`

Explanation

To solve the question, we need to identify the green oily compound formed when a small amount of potassium permanganate (KMnO4) is added to concentrated sulfuric acid (H2SO4).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are potassium permanganate (KMnO4) and concentrated sulfuric acid (H2SO4).

2. **Understand the Reaction**:
- When KMnO4 reacts with concentrated H2SO4, it undergoes a redox reaction. KMnO4 acts as an oxidizing agent.

3. **Determine the Product**:
- The main product formed in this reaction is manganese heptoxide (Mn2O7). This is a well-known compound that is dark green and has oily characteristics.

4. **Properties of the Product**:
- Manganese heptoxide (Mn2O7) is known to be highly explosive in nature. This aligns with the description given in the question.

5. **Evaluate the Options**:
- Now, let’s evaluate the options provided:
- Option 1: Mn2O7 (Manganese heptoxide) - This is the correct answer.
- Option 2: MnO7 - This is not a valid compound.
- Option 3: MnSO4 (Manganese sulfate) - This is not the product formed in this reaction.
- Option 4: Mn2O3 (Manganese(III) oxide) - This is also not the product formed in this reaction.

6. **Conclusion**:
- The compound formed is Mn2O7, which is the green oily compound that is highly explosive.

### Final Answer:
The compound obtained is **Mn2O7 (Manganese heptoxide)**.