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The equivalent mass of KMnO4 in alkaline...

The equivalent mass of `KMnO_4` in alkaline and neutral mediums is `ul"one-fifth"` of its molecular mass.

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To solve the question regarding the equivalent mass of `KMnO4` in alkaline and neutral mediums, we will follow these steps: ### Step 1: Understand the Molecular Mass of KMnO4 The molecular mass of `KMnO4` (Potassium permanganate) is calculated as follows: - Potassium (K) = 39.1 g/mol - Manganese (Mn) = 54.9 g/mol - Oxygen (O) = 16.0 g/mol × 4 = 64.0 g/mol ...
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Equivalent mass of KMnO_(4) in acidic basic and netural are in the ratio, of:

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Equivalent mass of KMnO_(4) is equal to one-fifth of its molecular mass when it acts as oxidising agent in mild basic medium. Reason (R): Oxidation number of Mn in KMnO_(4) is +7 .

n-Factor of KMnO_(4) in neutral medium is

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STATEMENT-1: The equivalent mass of of KMnO_(4) in acidic medium is (M)/(5) where M=molecular mass of KMnO_(4) STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

The equivalent mass of dilvalent metal is W. The molecular mass of its chloride is:

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Equivalent mass of KMn O_4 in acidic and basic medium respectively [M = Molar mass of KMn O_4 ]

Assertion: Equivalent mass of KMnO_4 is same in the neutral as well as alkaline medium. Reason: The product formed in both cases in MnO_2

Molecular weight of KMnO_(4) in acidic medium and neutral medium will be respecitvely -