Home
Class 12
CHEMISTRY
How would you accont for the following? ...

How would you accont for the following?
Lanthanoids form primarily + 3 ions, while the actinoids usually have higher oxidation states in their compounds, + 4 or even +6 being typical.

Text Solution

AI Generated Solution

To account for the difference in oxidation states between lanthanoids and actinoids, we can analyze the electronic configurations and the energy levels of the f-block elements. ### Step-by-Step Solution: 1. **Understanding the Electronic Configuration**: - Lanthanoids (elements 57 to 71) have their electrons filling the 4f subshell. - Actinoids (elements 89 to 103) have their electrons filling the 5f subshell, but they also have electrons in the 6d and 7s subshells. ...
Promotional Banner

Topper's Solved these Questions

  • d- AND- f- BLOCK ELEMENTS

    ICSE|Exercise EXERCISE (PART-II) (DESCRIPTIVE QUESTIONS)(SHORT ANSWER QUESTIONS)|50 Videos
  • d- AND- f- BLOCK ELEMENTS

    ICSE|Exercise EXERCISE (PART-II) (DESCRIPTIVE QUESTIONS)(LONG ANSWER QUESTIONS)|51 Videos
  • d- AND- f- BLOCK ELEMENTS

    ICSE|Exercise EXERCISE (PART-I)(MATCH AND FOLLOWINGS):|1 Videos
  • COORDINATION COMPOUNDS

    ICSE|Exercise ISC EXAMINATION QUESTION (PART- II DESCRIPTIVE QUESTIONS)|39 Videos
  • DISTINCTION BETWEEN PAIRS OF COMPOUNDS

    ICSE|Exercise QUESTIONS |155 Videos

Similar Questions

Explore conceptually related problems

How would you account for the following : (i) Among lanthanoids , Ln(III) compounds are predominant , However, occasionally in solutions or in solid compounds , +2 and +4 ions are also obtained . (ii) The E_(M2+//M)^(@) for copper is positive (0.34V ) . Copper is the only metal in the first series of transition elements showing this behaviour . (iii) The metallic radii of the third (5d) series of transition metals are nearly the same as those of the corresponding members of the second series .

In which of the following ions does the metal have an oxidation state +3 ?

How would you account for the following? (l) Transition metals exhibit variable oxidation states. (ii) Zr (Z = 40) and Hf (Z = 72) have almost identical radii.

How would you account for the following : [Fe(CN)_6]^(3-) is weakly paramagnetic while [Fe(CN)_6]^(4-) is diamagnetic

How would you account for the following : Ni(CO)_4 possesses tetrahedral geometry while [Pt(NH_3)_2Cl_2] is square planar.

(a) (i) Complete the following chemical equations : (i) NaOH_((aq))+Cl_(2(g)) rightarrow (Hot and conc.) (ii) Xef_(6)(s)+H_(2)O(l) rightarrow (b) How would you account for the following ? (i) The value of electron gain enthalpy with negative sign for sulphur is higher than that for oxygen. (ii) NF_(3) is an exothermic compound but NCl_(3) is endothermic compound. (iii) ClF_(3) molecule has a T-shaped structure and not a trigonal planar one.

How would you account for the following? (i)The atomic radii of the metals of the third (5d) series of transition elements are virtually the same as those of the corresponding members of the second (4d) series. (ii)The E^(@) value for the Mn^(3+)//Mn^(2+) couple is much more positive than that for Cr^(3+)//Cr^(2+) couple or Fe^(3+)//Fe^(2+) couple. (iii)The highest oxidation state of a metal is exhibited in its oxide or fluoride.

How would you account for the following : (i) The metallic radii of the third (5d) series of transition metals are virtually the same as those of the corresponding group members of the seconds (4d) series. (ii) There is a greater range of oxidation states among the actinoids than among the lanthanoids.

How would you account for the following? (i) Transition metals exhibits variable oxidation state. (ii) Zr(Z=40) and Hf(Z=72) have almost identical radii. (iii) Transition metals and their compounds act as catalyst. OR Complete the following chemical equation: (i) Cr_(2)O_(7)^(2-)+6Fe^(2+)+14H^(+)rarr (ii) CrO_(4)^(2-)+2H^(+)rarr (iii) 2MnO_(4)^(2-)+5C_(2)O_(4)^(2-)+16H^(+)rarr

How would you account for the fact that actinoids exhibit a larger number of oxidation state than the corresponding lanthanoids?

ICSE-d- AND- f- BLOCK ELEMENTS-EXERCISE (PART-II) (DESCRIPTIVE QUESTIONS)(VERY SHORT ANSWER QUESTIONS)
  1. Which is more basic La(OH)(3)zor Lu(OH)3 ? Why?

    Text Solution

    |

  2. What is the basic difference between the electronic configurations of ...

    Text Solution

    |

  3. Why do transition elements show similarities along the horizontal peri...

    Text Solution

    |

  4. Why the third ionization energy of manganese (atomic number 25) unexpe...

    Text Solution

    |

  5. Which property of the transition elements makes them good catalysts?

    Text Solution

    |

  6. What are coinage metals ?

    Text Solution

    |

  7. Write the ionic reaction for the reaction between MnO4^(-) ions and ox...

    Text Solution

    |

  8. Write one reaction using alkaline KmnO4.

    Text Solution

    |

  9. Write the electronic configuration of the element with atomic number 1...

    Text Solution

    |

  10. What is the electronic cofiguration of charomium atom (z= 24) Give re...

    Text Solution

    |

  11. Why are Cd^(2+) salts white ?

    Text Solution

    |

  12. Though a transition element, scandium (Z = 21) does not exhibit variab...

    Text Solution

    |

  13. Account for the following: There are irregularities in the electron...

    Text Solution

    |

  14. The gradual decrease in size (actionoid contraction) is from element t...

    Text Solution

    |

  15. (a) Complete the following chemical equations : (i) MnO(4)^(-) (aq) ...

    Text Solution

    |

  16. Assign reasons for the following : (i) Copper (I) ion is not known i...

    Text Solution

    |

  17. Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) con...

    Text Solution

    |

  18. How would you accont for the following? Lanthanoids form primarily +...

    Text Solution

    |

  19. How would you account for the following : (i) Among lanthanoids , Ln...

    Text Solution

    |

  20. Explain the following observations : (i) Many of the transition elem...

    Text Solution

    |