A proton enters a region of uniform magnetic field `B` of `0.5T` with a velocity `u` at an angle `45^(@)` with `B` .If `P` is the pitch of the helical path followed,the radius of the helix is :?

A charged particle enters a uniform magnetic field with velocity vector at angle of 45^@ with the magnetic field. The pitch of the helical path followed by the particle is p. the radius of the helix will be

A charged enters a unifrom magnetic field with velocity vector at an angle of 45^(@) with the magnetic field . The pitch of the helical path followed by the particles is rho . The radius of the helix will be

A beam of electrons enters a uniform magnetic field of 0*3T with a velocity of 4xx10^5ms^-1 at an angle of 60^@ to the field. Find the radius of the helical path taken by the beam. Also find the pitch of the helix (distance travelled by a proton parallel to the magnetic field during one period of rotation). Mass of proton is 1*67xx10^(-27)kg .

A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A beam of protons enters a uniform magnetic field of 0.3T with velocity of 4xx10^5m//s in a direction making an angle of 60^(@) with the direction of magnetic field. The path of motion of the particle will be

A proton enter in a uniform magnetic field of 2.0 mT at an angle of 60degrees with the magnetic field with speed 10m/s. Find the picth of path

A beam of protons enters a uniform magnetic field of 0.3 tesla with a velocity of 4xx10^(5) m/s at an angle of 60º to the field. Then, (Mass of the proton =1.7 xx10^(-27) kg.) (1) the radius of the helical path is 1.226 xx 10^(-2) m (2) the pitch of the helix is 4.45 xx 10^(-2) m (3) the radius of the helical path is 1.226 xx 10^(-3) m (4) the pitch of the helix is 4.45xx10^(-4) m