In Young's experiment intensity at a point on the scrren is 75% of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be

For minimum intensity the phase difference between the two waves is

If path difference between two interfering waves arriving at a point is zero, then the point will

In Young's double-slit experiment, the intensity at a point P on the screen is half the maximum intensity in the interference pattern. If the wavelength of light used is lambda and d is the distance between the slits, the angular separation between point P and the center of the screen is

In young's experiement, a creast of one wave coincides with the through of the other wave at a point. The phase difference between the two waves is

In Young's double slit experiment intensity at a point is ((1)/(4)) of the maximum intersity. Angular position of this point is

In Young's double slit experiment, the phase difference between the two waves reaching at the location of the third dark fringe is

In Young's double slit experiment the phase difference between the waves reaching the central fringe and fourth bright fringe will be

The intensity on the screen at a certain point in a double-slit interference patteren is 25.0% of the maximum value. (a) What minimum phase difference (in radians) between the sources produces this result? (b) Express this phase difference as a path difference for 486.1 nm light.