Find the maximum kinetic enegry of photoelectrons liberated form the surface of lithium by electromagnetic radiation whose electric component varies with time as `E = a(1+cos omegat) cos omega_(0)t`, where `a` is a constant, `omega = 6.10^(14)s^(-1)` and `omega_(0) = 360.10^(15)s^(-1)`.(Work function of Lithiuim = 2.39eV)

Find the maximum kinetic enegry of photoelectrons liberated form the surface of lithium by electromagnetic radiation whose electric component varies with time as E = a(1+cos omegat) cos omega_(0)t , where a is a constant, omega = 6.0.10^(14)s^(-1) and omega_(0) = 360.10^(15)s^(-1) .

The surface of a metal of work funcation phit is illumicated by light whose electric field component varies with time as E = E_(0) [1 + cos omegat] sinomega_(0)t . Find the maximum kinetic energy of photonelectrons emitted from the surface.

The maximum kinetic energy of photoelectrons ejected from a metal, when it is irradiated with radiation of frequency 2xx10^(14)s^(-1) is 6.63xx10^(-20) J. the threshold frequency of the metal is:

What will be the maximum kinetic energy of the photoelectrons ejected from magnesium (for which the work -function W=3.7 eV) when irradiated by ultraviolet light of frequency 1.5xx10^15 s^(-1) .

Electromagnetic radiation whose electric component varies sinusoidally with time as E=C_1(C_2+C_3 cos omegat) cos omega_0t , "where" C_1, C_2 and C_3 are constants in incident on lithium and liberates photoelectrons. If the kinetic energy of the most energetic photoelectrons be 0.592 xx10^(-19) J find the work function of lithium given that omega_0= 3.6 xx10^(15) rad/sec and omega=6 xx10^(14) rad/sec.

Calculate the kinetic energy of a photoelectron (in eV) emitted on shining light of wavelength 6.2 xx 10^(-6)m on a metal surface. The work function of the metal is 0.1 eV ?

If the reading of the voltmeters vary with time as: V_(1) = 20 sin omega t and V_(2) = - 20 cos (omega t + (pi)/(6)) then the unknown circuit element x is a: