A current `i` ampere flows in a circular arc of wire whose radius is `R`, which subtend an angle `3pi//2` radian at its centre. The magnetic induction `B` at the centre is

A circular arc of wire of radius of curvature r subtends an angle of p/4 radian at its centre. If i current is flowing in it then the magnetic induction at its centre is -

An arc of a circle of raduis R subtends an angle (pi)/2 at the centre. It carriers a current i . The magnetic field at the centre will be

Consider a circular arc of radius R which subtends an angle phi at its centre .Let us calculate the electric field strength at C

A piece of wire carrying a current of 6.00 A is bent in the form of a circular arc of radius 10.0 cm, and it subtends an angle of 120^@ at the centre. Find the magnetic field B due to this piece of wire at the centre.

Two long straight wires are connected by a circular section which has a radius R . All the three segments lie in the same plane and carry a current I . The magnetic induction at the centre O of the circular segments is

A battery is connected between two points A and B on the circumference of a uniform conducting ring of radius r and resistance R . One of the arcs AB of the ring subtends an angle theta at the centre . The value of the magnetic induction at the centre due to the current in the ring is

Current I A flowing in a circular coil of radius r. then the magnetic induction at the centre is B. If the current is doubled then the magnetic induction will be